The following equation represents double displacement reaction, what is the precipitate formed in this reaction?

$A g N O_{3} (a q) + N a I (a q) \to A g I (s) + N a N O_{3} (a q)$

Silver iodide

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Sodium nitride

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Sodium iodide

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Silver nitrate

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Solution

The correct option is A
Silver iodide

$A g N O_{3} (a q) + N a I (a q) \to A g I (s) + N a N O_{3} (a q)$

In the above reaction, the product silver iodide is insoluble as the physical state (solid) is mentioned for it in the reaction. The solid product in double displacement reaction will be a precipitate.

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Similar questions

Q. Silver iodide is precipitated when silver nitrate reacts with sodium iodide.

(a) When you have mixed the solutions of lead(II) nitrate and potassium iodide,
(i) what was the colour of the precipitate formed and can you name the precipitate?
(ii) write the balanced chemical equation for this reaction.

(b) What is the difference between displacement and double displacement reactions? Write equations for these reactions.

50.0 m L

0.10 M

sodium chloride solution is mixed with

25.0 m L

0.25 M

silver nitrate solution. What mass of silver chloride should form from this reaction?

Q. When solutions of sodium chloride is mixed with silver nitrate, what is/are the precipitate(s) formed?

During the reaction of silver nitrate with hydrochloric acid, the white precipitate X is formed. This precipitate is insoluble in _____.

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The following equation represents double displacement reaction, what is the precipitate formed in this reaction? AgNO3(aq)+NaI(aq)→AgI(s)+NaNO3(aq)

The correct option is A Silver iodide AgNO3(aq)+NaI(aq)→AgI(s)+NaNO3(aq) In the above reaction, the product silver iodide is insoluble as the physical state (solid) is mentioned for it in the reaction. The solid product in double displacement reaction will be a precipitate.

The following equation represents double displacement reaction, what is the precipitate formed in this reaction?

$A g N O_{3} (a q) + N a I (a q) \to A g I (s) + N a N O_{3} (a q)$