Question

The following equation represents the double displacement reaction.What is the precipitate formed in this reaction?

$AgN{O}_3\left(aq\right)+NaI\left(aq\right)\to AgI\left(s\right)+NaN{O}_3\left(aq\right)$

• A. Silver iodide
• B. Sodium nitride
• C. Sodium iodide
• D. Silver nitrate

Answer 1

The correct option is A

Silver iodide

$AgN{O}_3\left(aq\right)+NaI\left(aq\right)\to AgI\left(s\right)+NaN{O}_3\left(aq\right)$

In the above reaction silver iodide is insoluble as the physical state of the reaction is mentioned. The double displacement reaction implies a precipitation reaction. So the solid product formed in the double displacement reaction will be a precipitate. The precipitate in this reaction is silver iodide.