The following equation represents the double displacement reaction.What is the precipitate formed in this reaction?
AgNO3(aq)+NaI(aq)→AgI(s)+NaNO3(aq)
Silver iodide
AgNO3(aq)+NaI(aq)→AgI(s)+NaNO3(aq)
In the above reaction silver iodide is insoluble as the physical state of the reaction is mentioned. The double displacement reaction implies a precipitation reaction. So the solid product formed in the double displacement reaction will be a precipitate. The precipitate in this reaction is silver iodide.