Question

The following equilibrium are given
$N_2+3H_2\to 2N{H}_3-K_1$
$N_2+O_2\to 2NO-K_2$
$H_2+1/2O_2\to H_{2}O-K_3$
The equilibrium constant of reaction,
$3H_2+5/2O_2\to 2NO+3H_{2}O$, in terms of $K_1,K_2,K_3$

• A. $K_1{K}_2/K_3$
• B. $K_1{K}_3/K_2$
• C. $K_2{K}_3/K_1$
• D. $K_1{K}_2{K}_3$

Answer 1

Answer: (C)

$K_2{K}_3/K_1$

$K_1=\frac{P_{{NH}_3^2}}{P_{N_2}\cdot P_{H_2^3}},K_2=\frac{P_{NO}^2}{P_{N_2}\cdot P_{O_2}},K_3=\frac{P_{H_{2}O}}{P_{H_2}\cdot P_{O_2}^{1/2}}$

For the following reaction, Let eqn const be $K$.

${2NH}_3+5/2O_2⟶2NO+3H_{2}O$

$K=\frac{K_2\cdot K_3}{K_1}$