The following equilibrium constants are givenN2-3H2-2NH3-K1N2-O2-2NO-K2H2-12O2-H2O-K3The equilibrium constant for the oxidation of the NH3 by oxygen to give NO is-

(I) N_2+3H_2⇌2NH_3;K_1=[NH_3]^2[N_2][H_2]^3 (II) N_2+O_2⇌2NO;K_2=[NO]^2[N_2][O_2] (II I) H_2+12O_2⇌H_2O;K_3=[H_2O][H_2][O_2]^0.5 II +(3× III) − II will ...

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Standard XII

Chemistry

Effective Equilibrium Constant

The following...

Question

The following equilibrium constants are given
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}$
$N_{2} + O_{2} ⇌ 2 N O; K_{2}$
$H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3}$
The equilibrium constant for the oxidation of the $N H_{3}$ by oxygen to give $N O$ is:

\frac{K_{1} \times K_{2}}{K_{3}}

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\frac{K_{2} \times K_{3}^{3}}{K_{1}}

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\frac{K_{2} \times K_{3}^{2}}{K_{1}}

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\frac{K_{2}^{2} \times K_{3}}{K_{1}}

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Solution

The correct option is B $\frac{K_{2} \times K_{3}^{3}}{K_{1}}$
$(I) N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1} = \frac{[N H_{3}]^{2}}{[N_{2}] [H_{2}]^{3}}$
$(I I) N_{2} + O_{2} ⇌ 2 N O; K_{2} = \frac{[N O]^{2}}{[N_{2}] [O_{2}]}$
$(I I I) H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3} = \frac{[H_{2} O]}{[H_{2}] [O_{2}]^{0.5}}$

$I I + (3 \times I I I) - I I$ will give
$2 N H_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O; K = \frac{K_{2} \times K_{3}^{3}}{K_{1}}$

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Similar questions

The following equilibrium constants are given

$N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}$

$N_{2} + O_{2} ⇌ 2 N O; K_{2}$

$H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O; K_{3}$

The equilibrium constant for the oxidation of $N H_{3}$ by oxygen to give $N O$ is:

Q. The equilibrium constants for the following are:

N_{2} + 3 H_{2} ⇌ 2 N H_{3} K_{1}

N_{2} + O_{2} ⇌ 2 N O K_{2}

H_{2} + \frac{1}{2} O_{2} \to H_{2} O K_{3}

The equilibrium constant (K) of the reaction:

2 N H_{3} + \frac{5}{2} O_{2} K ⇌ 2 N O + 3 H_{2} O,

will be

Q. At

25^{o}

C, the equilibrium constants

K_{1}, K_{2}

and

K_{3}

of three reactions are:

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

N_{2} + O_{2} ⇌ 2 N O; K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3}

The equilibrium constants for the oxidation of

N H_{3}

by oxygen to given

N O

is:

Q. Given:

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g); K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

Calculate the equilibrium constant for the reaction,

2 N H_{3} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

Q. Given:

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g); K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

where

K_{1}, K_{2}, K_{3}

are equilibrium constants.
The equilibrium constant for the reaction,

2 N H_{3} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

will be:

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The following equilibrium constants are given N2+3H2⇌2NH3;K1 N2+O2⇌2NO;K2 H2+12O2⇌H2O;K3 The equilibrium constant for the oxidation of the NH3 by oxygen to give NO is:

The correct option is B K2×K33K1(I) N2+3H2⇌2NH3;K1=[NH3]2[N2][H2]3 (II) N2+O2⇌2NO;K2=[NO]2[N2][O2] (III) H2+12O2⇌H2O;K3=[H2O][H2][O2]0.5 II+(3×III)−II will give 2NH3+52O2⇌2NO+3H2O;K=K2×K33K1

The following equilibrium constants are given
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}$
$N_{2} + O_{2} ⇌ 2 N O; K_{2}$
$H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3}$
The equilibrium constant for the oxidation of the $N H_{3}$ by oxygen to give $N O$ is: