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Question

The following equilibrium constants were determined at 1120 K:
2CO(g)C(s)+CO2(g);  KP1=1014atm1CO(g)+Cl2(g)COCl2(g);   Kp2=6×103atm1
What is the equilibrium constant KC for the following reaction at 1120 K;
C(s)+CO2(g)+2Cl2(g)2COCl2(g)
  1. 5.51×106M1
  2. None of these
  3. 3.31×1011M1
  4. 5.5×1010M1


Solution

The correct option is C 3.31×1011M1
C(s)+CO2(g)2CO(g);Kp=1014atm2CO(g)+2Cl2(g)2COOCl2;KP2=(6×103)2atm2
Add (1) and (2)
C(s)+CO2+2Cl2(g)2COCl2(g)Kp=1014×36×106=36×108 atm1
We know that Kp=Kc×(RT)ΔngKc=Kp×(RT)Δng
For given reaction Δng=1Kc=Kp(RT)=36×108 atm1×0.0821 L atm K1 mol1×1120Kc=3.31×1011M1

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