The following facts are available-2 A - circleddash - B - 2 rightarrow 2 B - -circleddash - A - 2 -Which of the following statement is correct- A- E C - C 2- E B - B 2- E A - A 2- E D - D 2-B- E C - C 2- E B - B 2- E D - D 2-

The correct option is C E^∘_C^⊝|C_2 lt; E^∘_B^⊝|B_2 lt; E^∘_A^⊝|A_2 lt; E^∘_D^⊝|D_2 nbsp;Given examples are of non metals. A non metal having higher r ...

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Standard XII

Mathematics

Eccentricity of Hyperbola

The following...

Question

The following facts are available:
$2 A^{⊝} + B_{2} \to 2 B^{⊝} + A_{2}; 2 C^{⊝} + B_{2} \to N o r e a c t i o n; 2 D^{⊝} + A_{2} \to 2 A^{⊝} + D_{2}$
Which of the following statement is correct?

E_{C^{⊝} | C_{2}}^{\circ} > E_{B^{⊝} | B_{2}}^{\circ} > E_{A^{⊝} | A_{2}}^{\circ} > E_{D^{⊝} | D_{2}}^{\circ}

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E_{C^{⊝} | C_{2}}^{\circ} < E_{B^{⊝} | B_{2}}^{\circ} < E_{A^{⊝} | A_{2}}^{\circ} < E_{D^{⊝} | D_{2}}^{\circ}

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E_{C^{⊝} | C_{2}}^{\circ} < E_{B^{⊝} | B_{2}}^{\circ} > E_{A^{⊝} | A_{2}}^{\circ} > E_{D^{⊝} | D_{2}}^{\circ}

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E_{C^{⊝} | C_{2}}^{\circ} > E_{B^{⊝} | B_{2}}^{\circ} < E_{A^{⊝} | A_{2}}^{\circ} < E_{D^{⊝} | D_{2}}^{\circ}

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Solution

The correct option is B $E_{C^{⊝} | C_{2}}^{\circ} < E_{B^{⊝} | B_{2}}^{\circ} < E_{A^{⊝} | A_{2}}^{\circ} < E_{D^{⊝} | D_{2}}^{\circ}$

Given examples are of non-metals. A non-metal having higher reduction potential replaces the other from its solution.
Thus, $E_{R P D}^{\circ} < E_{R P A}^{\circ} < E_{R P B}^{\circ}$
Thus, $E_{O P D}^{\circ} > E_{O P A}^{\circ} > E_{O P B}^{\circ}$

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Similar questions

If $E_{A}, E_{B}, E_{C} a n d E_{D}$ represent the magnitudes of electric fields at A, B, C and D. Which of the options are correct?

If a, b, c, d are in G.p., prove that :

(i) $(a^{2} + b^{2}), (b^{2} + c^{2}), (c^{2} + d)^{2}$ are in G.P.

(ii) $(a^{2} - b^{2}), (b^{2} - c^{2}), (c^{2} - d)^{2}$ are in G.P.

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Q. Given a,b,c,d are in G.P then

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are in ........

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The following facts are available: 2A⊝+B2→2B⊝+A2;2C⊝+B2→ No reaction;2D⊝+A2→2A⊝+D2 Which of the following statement is correct?

The correct option is B E∘C⊝|C2<E∘B⊝|B2<E∘A⊝|A2<E∘D⊝|D2 Given examples are of non-metals. A non-metal having higher reduction potential replaces the other from its solution. Thus, E∘RPD<E∘RPA<E∘RPB Thus,E∘OPD>E∘OPA>E∘OPB

The following facts are available:
$2 A^{⊝} + B_{2} \to 2 B^{⊝} + A_{2}; 2 C^{⊝} + B_{2} \to N o r e a c t i o n; 2 D^{⊝} + A_{2} \to 2 A^{⊝} + D_{2}$
Which of the following statement is correct?