The following figure shows a quadrilateral in which sides AB and DC are parallel. If ∠A:∠D=4:5, ∠B=(3x−15)o and ∠C=(4x+20)o, find each angle of the quadrilateral ABCD.
Let ∠A=4x∠D=5xSince ∠A+∠D=180o [∵AB||DC]∴4x+5x=180o⇒9x=180o⇒x=20o∴∠A=4(20)=80o, ∠D=5(20)=100oAgain ∠B+∠C=180o [∵AB||DC]∴3x−15o+4x+20o=180o7x=180o−5o⇒7x=175o⇒x=25o∴∠B=75o−15o=60oand ∠C=4(25)+20=100o+20o=120o.