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Question

The following figure shows a quadrilateral with sides AB and DC parallel to each other.

If A:D=4:5

B=(3x15) and

C=(4x+20)

Which of the following options is/are correct ?


A

A=100

B=60

C=120

D=80

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B

A=120

B=60

C=120

D=80

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C

A=80

B=60

C=120

D=100

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D

A=80

B=120

C=60

D=100

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Solution

The correct option is C

A=80

B=60

C=120

D=100


The given figure is a trapezium as it has one pair of parallel sides.

Given: B=(3x15) and C=(4x+20)

B+C=180 (Cointerior angles)

(3x15)+(4x+20)=180

7x+5=180

7x=1805=175

x=1757=25

B=3x15=3×2515=7515

B=60

C=4x+20=4×25+20=100+20

C=120

Given: A:D=4:5

Let A=4y, D=5y

A+D=180 (Cointerior angles)

4y+5y=180

9y=180

y=20

A=4y=4×20

A=80

D=5y=5×20

D=100


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