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Question

The following figures are parallelograms. Find the degree values of the unknowns x, y, z.

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Solution

(i)Opposite angles of a parallelogram are same. x=z and y=100°Also, y+z=180° (sum of adjacent angles of a quadrilateral is 180°)z+100°=180°x=180°-100°x=80° x=80°, y=100° and z=80°(ii)Opposite angles of a parallelogram are same. x=y and RQP=100°PSR+SRQ=180°y+50°=180°x=180°-50°x=130° x=130°, y=130° Since y and z are alternate angles, z=130°.(iii)Sum of all angles in a triangle is 180°.30°+90°+z=180°z=60°Opposite angles are equal in parallelogram. y=z=60°and x=30° (alternate angles)(iv)x=90° (vertically opposite angle)Sum of all angles in a triangle is 180°. y+90°+30°=180°y=180°-(90°+30°)=60°y=z=60° (alternate angles)(v)Opposite angles are equal in a parallelogram. y=80°y+x=180° x=180°-100°=80°z=y=80° (alternate angles)(vi)y=112° (opposite angles are equal in a parallelogram)In UTW :x+y+40°=180° (angle sum property of a triangle)x=180°-(112°-40°)=28°Bottom left vertex=180°-112°=68° z=x=28° (alternate angles)

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