The following frequency distribution showing the marks obtained by $25$ students in science subject. Find the mean using Assumed mean method.

90

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91

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92

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93

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Solution

The correct option is C $92$
Answer:- By shortcut Method

Marks
(x) Students
(f) d=x-A fd
90 3 -2 -6
91 4 -1 -4
92=A 5 0 0
93 6 1 6
94 7 2 14
$Σ f = 25$ $Σ f d = 10$
Mean = $A + \frac{Σ f d}{Σ f} = 92 + \frac{10}{25} = \frac{92 + 0.4}{=} 92.4 ≃ 92$
C)92

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Marks (x)	Students (f)	d=x-A	fd
90	3	-2	-6
91	4	-1	-4
92=A	5	0	0
93	6	1	6
94	7	2	14
	$Σ f = 25$		$Σ f d = 10$

The following frequency distribution showing the marks obtained by 25 students in science subject. Find the mean using Assumed mean method.

The correct option is C 92Answer:- By shortcut MethodMarks(x) Students(f) d=x-A fd 903-2-6914-1-492=A50093616947214 Σf=25 Σfd=10 Mean = A+ΣfdΣf=92+1025=92+0.4=92.4≃92C)92

The following frequency distribution showing the marks obtained by $25$ students in science subject. Find the mean using Assumed mean method.

The correct option is C $92$
Answer:- By shortcut Method

Marks
(x) Students
(f) d=x-A fd
90 3 -2 -6
91 4 -1 -4
92=A 5 0 0
93 6 1 6
94 7 2 14
$Σ f = 25$ $Σ f d = 10$
Mean = $A + \frac{Σ f d}{Σ f} = 92 + \frac{10}{25} = \frac{92 + 0.4}{=} 92.4 ≃ 92$
C)92