Question

The following frequency table shows that the demand for a sweet and the number of customers. Find the mode of demand of sweet.

Weight of sweet (in gram)	$0-250$	$250-500$	$500-750$	$750-1000$	$1000-1250$
No. of customers	$10$	$60$	$25$	$20$	$15$

Answer 1

Here highest frequency is $60$ so, the modal class will be $250-500.$

Now we have,

$l=250$

$f_0=10$

$f_1=60$

$f_2=25$

$h=250$

Now, we will substitute the above values in,

$\begin{array}{cc}\text{Mode}& =l+\left(\frac{f_1-f_0}{2f_1-f_0-f_2}\right)\times h\\ & =250+\left(\frac{60-10}{2\times 60-10-25}\right)\times 250\\ & =250+\left(\frac{50}{85}\right)\times 250\\ & =250+147.06\\ & =397.06\end{array}$

Hence, the mode weight of demand of sweet is $397.06\text{gm}.$