Question

The following gases occupy same volume at STP.

• A. 14 g of nitrogen
• B. 22 g of carbon dioxide
• C. 32 g of sulphur dioxide
• D. 32 g of oxygen

Answer 1

Answer: (A), (B), (C)

The correct options are
A 14 g of nitrogen
B 22 g of carbon dioxide
C 32 g of sulphur dioxide

AT $STP$, $1$ mole of any element / compound occupies $22.4l$

$\ast$ $14g$ of $N_2=0.5$ mole of $N_2$

Molecular weight of $N_2$ $=28g$

$\therefore$ it occupies $22.4l\times 0.5=11.2l$

$\ast$ $22g$ of ${CO}_2$

molecular weight of ${CO}_2=12+2\times 16=44gm$

$\therefore$ moles of ${CO}_2=\frac{22}{44}=0.5$

$\therefore$ it occupies $0.5\times 22.4=11.2l$

$\ast$ $32g$ of ${SO}_2$

molecular weight of ${SO}_2=32+16\times 2=64g$

$\therefore$ moles of ${SO}_2=\frac{32}{64}=0.5$

$\therefore$ volume occupies $=0.5\times 22.4=11.2l$

$\ast$ $32gm$ of $O_2$

molecular weight of $O_2=16\times 2=32g$

$\therefore$ no. of moles of $O_2=\frac{32}{32}=1$

$\therefore$ volume occupied $=1\times 22.4=22.4l$