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Question

The following graph correctly reflects log P vs log (1V) for a finite amount of gas at a constant temperature.

K is a constant.


A

True

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B

False

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Solution

The correct option is A

True


According to Boyle's Law,

v1p P=KV

Take log on both sides.

Log P = log1V + log K

Now, comparing it to

Y= mn + c [Straight line]

Therefore, log p and log 1V should be a straight line with slope = log k


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