The following graph correctly reflects log P vs log (1V) for a finite amount of gas at a constant temperature.
K is a constant.
True
According to Boyle's Law,
v∝1p ⇒P=KV
Take log on both sides.
Log P = log1V + log K
Now, comparing it to
Y= mn + c [Straight line]
Therefore, log p and log 1V should be a straight line with slope = log k