The following graph shows the velocity of a moving object with time. The magnitude of the acceleration is maximum.

A

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between

A

and

B

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E

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between

C

and

D

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Solution

The correct option is D between $C$ and $D$
$A c c e l e r a t i o n = \frac{c h a n g e i n v e l c i t y}{t i m e}$
$a = \frac{d v}{d t} (s l o p e o f v - t g r a p h)$
Slope is negative but large in magnitude between curve path CD.
Hence, between C and D acceleration is maximum.

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Figure

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The following graph shows the velocity of a moving object with time. The magnitude of the acceleration is maximum.

The correct option is D between C and DAcceleration=changeinvelcitytimea=dvdt(slopeofv−tgraph)Slope is negative but large in magnitude between curve path CD.Hence, between C and D acceleration is maximum.

The correct option is D between $C$ and $D$
$A c c e l e r a t i o n = \frac{c h a n g e i n v e l c i t y}{t i m e}$
$a = \frac{d v}{d t} (s l o p e o f v - t g r a p h)$
Slope is negative but large in magnitude between curve path CD.
Hence, between C and D acceleration is maximum.