The following is a cyclic silicate

Phenacite

(B e_{2} S i O_{4})

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Thorteveitite

(S c_{2} S i_{2} O_{7})

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Beryl

(B e_{3} A l_{2} S i_{6} O_{18})

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Feldspar

(K A l S i_{3} O_{8})

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Solution

The correct option is C Beryl $(B e_{3} A l_{2} S i_{6} O_{18})$
Gen formula of cyclic silicate is $(S i O_{3})_{n}^{2 n -}$

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