The following is a list of methods for the preparation of salts.

A - direct combination of two elements.

B - reaction of a dilute acid with a metal.

C - reaction of a dilute acid with an insoluble base.

D - titration of a dilute acid with a solution of soluble base.

E - reaction of two solutions of salts to form a precipitate.

Choose from the above list A to E, the best method of preparing the following salts by giving a suitable equation in each case :

1. Anhydrous ferric chloride, 2. Lead chloride,

3. Sodium sulphate, 4. Copper sulphate.

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Solution

1. Anhydrous ferric chloride: - A (Direct combination of two elements)

$2 F e + 3 C l_{2} ⟶ 2 F e C l_{3}$

2. Lead chloride: - E (Reaction of two solutions of salts to form a precipitate

$P b (N O_{3})_{2} + 2 H C l ⟶ P b C l_{2} + 2 H N O_{3}$

3. Sodium sulphate: - D (Titration of dilute acid with a solution of soluble base)

$2 N a O H + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H_{2} O$

4. Copper sulphate:- C (reaction of a dilute acid with an insoluble base)

$C u (O H)_{2} + H_{2} S O_{4} ⟶ C u S O_{4} + 2 H_{2} O$

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H_{2} S O_{4}

Salt	Method of Preparation
Ammonium sulphate Calcium carbonate Iron (III) chloride Lead nitrate Zinc sulphate	E

The question refer to the following salt solutions listed (1) to (6).

Which two solutions will give a white precipitate when treated with dilute hydrochloric acid followed by barium chloride solution?

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