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Question

The following is a simplified diagram showing the fate of glucose during aerobic and anaerobic respiration. Identify the end products that are formed at stages indicated A, B, C and D. Identify the correct option from those given below.

A
A- Carbon dioxide and water, B- Pyruvic acid, C- Ethyl alcohol and carbon dioxide, D- lactic acid
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B
A – Pyruvic acid, B- Carbon dioxide and water, C-lactic acid, D-Ethyl alcohol and carbon dioxide, D- lactic acid
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C
A – Pyruvic acid, B- Carbon dioxide and water, C- Ethyl alcohol and carbon dioxide, D – Lactic acid
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D
A – Pyruvic acid, B-Ethyl alcohol and carbon dioxide, C-lactic acid, D- Carbon dioxide and water
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Solution

The correct option is C A – Pyruvic acid, B- Carbon dioxide and water, C- Ethyl alcohol and carbon dioxide, D – Lactic acid

The product of glycolysis is A. pyruvic acid, the pyruvate formed enters the Kreb's cycle in aerobic respiration and the products of Kreb’s cycle are CO2 and water. Therefore B. is carbon dioxide and water. In the absence of oxygen the glycolytic product pyruvate enters the anaerobic pathway, it then undergoes fermentation to form either ethylalcohol or lactic acid. Formation of ethylalcohol is accompanied by formation of carbon dioxide. Therefore C. is ethyl alcohol and carbon dioxide and D. is lactic acid.


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