Question

The following is a simplified scheme showing the fate of glucose during aerobic and anaerobic respiration. Identify the end products that are formed at stages indicated as A, B, C and D
Identify the correct option from those given below.

• A. A-Carbon dioxide and water, B-Pyruvic acid, C-Ethyl alcohol and carbon dioxide, D-Lactic acid
• B. A-Pyruvic acid, B-Carbon dioxide and water, C-lactic acid, D-Ethyl alcohol and carbon dioxide
• C. A-Pyruvic acid, B-Carbon dioxide and water, C-Ethyl alcohol and carbon dioxide, D-Lactic acid
• D. A-Pyruvic acid, B-Ethyl alcohol and cargon dioxide, C-Lactic acid, D-Carbon dioxide and water

Answer 1

The correct option is B A-Pyruvic acid, B-Carbon dioxide and water, C-lactic acid, D-Ethyl alcohol and carbon dioxide

The product of glycolysis is pyruvic acid (A), the products of krebs' cycle are $C{O}_2$ and water (B).
The product of fermentation in bacteria is lactic acid (C) while in yeast it is ethyl alcohol and $C{O}_2$ (D).