The following is an acid and also a conjugate base of another acid:

H S O_{4}^{-}

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H_{2} S O_{4}

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N O_{3}^{-}

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H_{3} O^{+}

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Solution

The correct option is B $H S O_{4}^{-}$
$H S O_{4}^{-} \to$ can accept $H^{+}$ and donate $H^{+}$

$H_{2} S O_{4} \to$ cannot accept $H^{+}$

$N O_{3}^{-} \to$ cannot donate $H^{+}$

$H_{3} O^{+} \to$ cannot accept $H^{+}$

Option A is correct.

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Similar questions

Conjugate base of the following reaction is

Reaction:H2SO4 + H2O (reversibly giving)H3O^+ + HSO4^-

Ans gn:H3O^+ ,H2SO4

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H C l

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(S O_{4}^{2 -})

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