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Question

The following is the c.d.f. of a discrete r.v. X:
X31013579
F(x)0.10.30.50.650.750.850.901
Find P(X3/X>0).

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Solution

P(X3)=P(X=3)+P(X=1)+P(X=0)+P(X=1)+P(X=3)
=0.1+0.2+0.2+0.5+0.1
=0.75
P(X>0)=P(X=1)+P(X=3)+P(X=5)+P(X=7)+P(X=9)
=0.15+0.1+0.1+0.05+0.1
=0.5
P(X3)P(X>0)=0.750.5=7.55=1.5
Hence, the answer is 1.5.


1229829_1347460_ans_88f3d900989944e986e0009c37468389.png

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