Question

The following observations have been arranged in ascending order.If the median of the data is 63,find the value of x:

29,32,48,50,x,x+2,72,78,84,95

Answer 1

Median=63

29,32,48,50,x,x+2,72,78,84,95

Here n=10 which is even

$\therefore Median=\frac{1}{2}[\frac{n}{2}thterm+(\frac{n}{2}+1)thterm]=\frac{1}{2}[\frac{10}{2}thterm+(\frac{10}{2}+1)thterm]=\frac{1}{2}[5thterm+6thterm]=\frac{1}{2}[x+x+2]=\frac{2x+2}{2}=x+1\therefore x+1=63\Rightarrow x=63-1=62Hencex=62$