The correct option is
B False
The following pair of linear equation can be written as
x+3y−11=0 and 4x+12y−22=0
Here, a1=1,b1=3,c1=−11
And, a2=4,b2=12,c2=−22
∴a1a2=14 and b1b2=312=14 and c1c2=−11−22=12
∴a1a2=b1b2≠c1c2
Thus, the given pair of linear equations are not consistent.