Question

The following plot is given between $KE$ on y-axis and frequency of radiation $\left(\nu \right)$ on x-axis. If slope of this plot is ${}^{\prime }{m}^{\prime }$ find ratio $\left(\frac{m}{h}\right)$ where $h=$ planck's constant.

Answer 1

The Eisenstein's photoelectric equation, $K_{max}=h\nu -W$ where W= work function. This is a equation like $y=mx-c$

So from the graph, slope, $m=h$ and intercept, $W=428.4$

Thus, $m/h=1$