Question

The following plot of volume vs pressure of a gas shows three different curves $\text{A},\text{B},$ and $\text{C}$ for different temperatures ${\text{T}}_1,{\text{T}}_2,$ and ${\text{T}}_3$. If ${\text{T}}_1<{\text{T}}_2<{\text{T}}_3$, match the curves with their correct temperatures.

• A. $\text{C}-{\text{T}}_1$
  $\text{B}-{\text{T}}_2$
  $\text{A}-{\text{T}}_3$
• B. $\text{C}-{\text{T}}_1$
  $\text{A}-{\text{T}}_2$
  $\text{B}-{\text{T}}_3$
• C. $\text{A}-{\text{T}}_1$
  $\text{B}-{\text{T}}_2$
  $\text{C}-{\text{T}}_3$
• D. $\text{B}-{\text{T}}_1$
  $\text{C}-{\text{T}}_2$
  $\text{A}-{\text{T}}_3$

Answer 1

The correct option is B $\text{C}-{\text{T}}_1$

$\text{A}-{\text{T}}_2$
$\text{B}-{\text{T}}_3$
Boyle's law states that when the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure.

$\text{P}\propto \frac{1}{\text{V}}$ or $\text{PV}=$ constant

For different temperatures, the curves of $\text{V}$ vs $\text{P}$ would look like as follows, with the curve corresponding to the highest temperature appearing the closest to the origin.

$⟹\text{C}-{\text{T}}_1;\text{A}-{\text{T}}_2;\text{B}-{\text{T}}_3$