The following rainfall data refers to station A and B which are equidistant from station X :
Station
A
Station
X
Station
B
Long - term normal annual rainfall in mm
200
250
300
Annual rainfall in mm for the year 1940
140
P
270
The value of P will be
A
250
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B
220
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C
205
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D
200
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Solution
The correct option is D 200 Since the normal annual rainfall at stations A and B does not lie within 10% of the normal annual rainfall at station X.
So, using normal ratio method, we get
P=2502[140200+270300]=200 mm
If the normal annual rainfall at non-missing station lie within 10% of that at missing station then arithmetic average method can be used.