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Le Chatelier's Principle for Del N Equals to 0

The following...

Question

The following reaction is known to occur in the human body:
${C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3} ⇌ H^{+} + H {C O}_{3}^{-}$
If ${C O}_{2}$ escapes from the system

pH will decrease

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H^{+}

ion concentration will decrease

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H_{2} {C O}_{3}

concentration will be unaltered

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The forward reaction will be promoted

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Solution

The correct option is B $H^{+}$ ion concentration will decrease
If $C O_{2}$ concentration will decrease then $H_{2} C O_{3}$ dissociates more towards left to give $C O_{2}$ and concentration of $H^{+}$ will decrease.

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Similar questions

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

({C O}_{2})

(H_{2} O)

H_{2} O + {C O}_{2} ⟶ H_{2} {C O}_{3}

H_{2} {C O}_{3} ⇌ H^{+} + H {C O}_{3}^{-}

{C O}_{2}

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

C O_{2}

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{- 1}

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

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