The following reaction occurs in the Blast Furnace where ion ore is reduced to iron metal :

$F e_{2} O_{3} (s) + 3 C O (g) ⇌ 2 F e (l) + 3 C O (g)$

Using Le Chatelier's principle, predict which of the following will not disturb the equilibrium?

Addition of

F e_{2} O_{3}

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Removal of

C O_{2}

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Removal of CO

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Addition of

C O_{2}

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Solution

The correct option is B Addition of $F e_{2} O_{3}$
$F e_{2} O_{3} + 3 C O ⇌ 2 F e + 3 C O$

According to Le Chatelier's principle change in concentration by changing the amount of reactant or product affect the equilibrium. However, the addition of solid reactant won't affect the concentration.
Therefore, addition of solid $F e_{2} O_{3}$ will not disturb the equilibrium.

Hence, the correct option is A.

Suggest Corrections

Similar questions

F e_{2} O_{3} (s) + 3 C O (g) ⇌ 2 F e (l) + 3 C O_{2} (g)

$F e_{2} O_{3} (s) + 3 C O (g) ⇌ 2 F e (s) + 3 C O_{2} (g)$

C + O_{2} \to C O_{2}

C O_{2} + C \to 2 C O

C a C O_{3} \to C a O + C O_{2}

C a O + S i O_{2} \to C a S i O_{3}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

F e_{2} O_{3} (s) + 3 C O (g) \to 3 C O_{2} (g) + 2 F e (l)

C + O_{2} \to C O_{2}

C O_{2} + C \to 2 C O

C a C O_{3} \to C a O + C O_{2}

C a O + S i O_{2} \to C a S i O_{3}

F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}

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