The following reactions are known to occur in the body. If $C O_{2}$ escapes from the system: $C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{- 1}$

pH will decreases

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hydrogen ion concentration will diminish

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H_{2} C O_{3}

concentration will remain unchanged

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the forward reaction will be favored

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Solution

The correct option is B hydrogen ion concentration will diminish
The equilibrium reaction is $C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{- 1}$ . When some $C O_{2}$ escapes from the body, the equilibrium will shift to left so that more $C O_{2}$ is produced which will nullify the effect of lost $C O_{2}$ . Due to this, the hydrogen ion concentration will decrease.

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Similar questions

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

C O_{2}

{C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3} ⇌ H^{+} + H {C O}_{3}^{-}

{C O}_{2}

When $C O_{2}$ is passed through water which of the following species will be present in water?

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