The following relations are defined on the set of real numbers check them for R,S,T.
aRb iff |a−b|>0
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Solution
Given aRbiff|a−b|>0;a,b∈R Reflexive : We know |a−a|≯0 Hence, a(∼R)a Hence, R is not reflexive. Symmetric: Let aRb ⇒|a−b|>0 ⇒|b−a|>0 ⇒bRa Hence, R is symmetric. Transitive: Let aRb,bRc ⇒|a−b|>0;|b−c|>0 ⇒|a−c|>0 R is transitive.