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Question

The following relations are defined on the set of real numbers check them for R,S,T.
aRb iff |ab|>0

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Solution

Given aRbiff|ab|>0;a,bR
Reflexive :
We know |aa|0
Hence, a(R)a
Hence, R is not reflexive.
Symmetric:
Let aRb
|ab|>0
|ba|>0
bRa
Hence, R is symmetric.
Transitive:
Let aRb,bRc
|ab|>0;|bc|>0
|ac|>0
R is transitive.

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