The following salt undergoes hydrolysis, and yet its aqueous solution in nearly neutral. The salt is:

N a^{+} C l^{-}

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N H_{4}^{+} C l^{-}

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C H_{3} C O O - N a^{+}

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C H_{3} C O O - N H_{4}^{+}

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Solution

The correct option is A $C H_{3} C O O - N H_{4}^{+}$
$C H_{3} C O O N H_{4}$ is salt of weak acid and weak base
$∴ C H_{3} C O O^{-} + H_{2} O \to C H_{3} C O O H + O H^{-}$
$N H 4^{+} + H_{2} O \to N H_{4} O H + H^{+}$
$H^{+} + O H^{-} \to H_{2} O$
Adding all three
$C H_{3} C O O^{-} + N H_{4}^{+} + H_{2} O \to C H_{3} C O O H + N H_{4} O H$
$∴$ Neutral

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