Question

The following sets are equal.
$A=\{x:x\in N;1<x<4\}$ and
$B=\{x:x$ is a solution of $x^2+5x+6=0\}$

• A. True
• B. False

Answer 1

The correct option is B False

$A=\{x:x\in N;1<x<4\}$
$=\{2,3\}$
$B=\{x:x$ is a solution of $x^2+5x+6=0\}$
The equation $x^2+5x+6=0\}$ can be solved as:
$x^2+5x+6=0\}$
or, $x^2+3x+2x+6=0$
or, $x(x+3)+2(x+3)=0$
or, $(x+3)(x+2)=0$
or, $x=-3$ or $x=-2$
$B=\{-2,-3\}$
$\therefore A\ne B$