Question

The following table gives the densty of pure substances.A rectangular sheet of a pure metal weighs about $515.9$ grams and measures $\frac{1}{4}$ inch by $2$ inches by $8$ inches. Assume the sheet is one of the metals in the table, which metal is it? (There are approximately $2.54$ centimeters in $1$ inch.)
Density $=\frac{Mass}{Volume}$.

Metal	Density$\left(g/c{m}^3\right)$
Copper	$8.96$
Iron	$7.87$
Nickel	$8.90$
Tin	$7.26$

• A. Copper
• B. Iron
• C. Nickel
• D. Tin

Answer 1

The correct option is B Iron

Weight of pure metal $=515.9$

Measure of metal $=(\frac{1}{4}\times 2.54)i(2\times 2.54)(8\times 2.54)$

Value of metal $=\frac{1}{24}\times 2\times 8\times (2.54{)}^3=4\times (2.54{)}^3=65.55{cm}^{3}Density=\frac{weight}{volume}=\frac{515.9}{65.55}=7.87So,givenmetalisIron$