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Byju's Answer
Standard X
Mathematics
Finding Mode for Grouped Data When Class Intervals Are Given
The following...
Question
The following table gives the distribution of the life time of 400 neon lamps:
Life time (in hours)
Number of lamps
1500
−
2000
2000
−
2500
2500
−
3000
3000
−
3500
3500
−
4000
4000
−
4500
4500
−
5000
14
56
60
86
74
62
48
Find the median life time of a lamp.
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Solution
Based on the given information, we can prepare the table shown above.
Here, we have,
n
=
400
⇒
n
2
=
200
The cumulative frequency just greater than
n
2
is
216
and the corresponding class is
3000
–
3500
.
Thus,
3000
–
3500
is the median class such that
n
2
=
200
,
l
=
3000
,
c
f
=
130
,
f
=
86
, and
h
=
500
We know that,
Median,
M
=
l
+
⎛
⎜ ⎜
⎝
n
2
−
c
f
f
⎞
⎟ ⎟
⎠
×
h
Where,
l
→
lower limit of the median class
n
→
total number of observations
(
∑
f
)
c
f
→
cumulative frequency of the class preceding the median class
f
→
frequency of the median class
h
→
class width
Substituting the corresponding values in the formula, we get:
M
=
3000
+
(
200
−
130
86
)
×
500
⇒
M
=
3000
+
70
86
×
500
=
3000
+
406.98
=
3406.98
Hence, median life time of a lamp is
3406.98
hours.
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Similar questions
Q.
The following table gives the distribution of the life time of
400
neon lamps:
Life time: (in hours)
Number of lamps
1500
−
2000
14
2000
−
2500
56
2500
−
3000
60
3000
−
3500
86
3500
−
4000
74
4000
−
4500
62
4500
−
5000
48
Find the median life.
Q.
The following table gives the distribution of the life time of 400 neon lamps:
Lite time:
(in hours)
Number of lamps
1500−2000
2000−2500
2500−3000
3000−3500
3500−4000
4000−4500
4500−5000
14
56
60
86
74
62
48
Find the median life.