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Question

The following table gives the lengths of three copper rods and their diameters. The resistances between the two ends of the rods arranged in ascending order is

RodLengthDiameter
Ald
B2l d/2
C l/2d
Dl d/2

A
A, B, C, D
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B
C, A, B, D
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C
C, A, D, B
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D
C, B, D, A
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Solution

The correct option is B C, A, D, B
RA=ρlπd24=4ρlπd2

RB=ρ2lπd216=32ρlπd2

RC=ρl2πd24=2ρlπd2

RD=ρlπd216=16ρlπd2

Increasing orderRC,RA,RD,RB

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