The following table gives the marks obtained by the students of a class in an exam out of 50 - begin array - c - c - WhineMarks - No- of Students lIHhlineBelow - 10 - 5 WlhlineBelow 20 - 10 Wlhline Below 30 - 23 WHhine Below 40 - 31 WhlineBelow 50 - 40 wlhlineend array i Convert the cumulative frequency distribution into a regular frequency distribution-ii Find the mean-A- 27B- 22C- 27-75D- 28

The correct option is C 27.75 [ Marks amp; No. of Students; 0 10 amp; 5; 10 20 amp; 5 ...

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Byju's Answer

Standard X

Mathematics

Frequency Polygon

The following...

Question

The following table gives the marks obtained by the students of a class in an exam out of 50.

$\begin{matrix} M a r k s & N o . o f S t u d e n t s B e l o w 10 & 5 B e l o w 20 & 10 B e l o w 30 & 23 B e l o w 40 & 31 B e l o w 50 & 40 \end{matrix}$

(i) Convert the cumulative frequency distribution into a regular frequency distribution.

(ii) Find the mean.

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27.75

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Solution

The correct option is C
27.75

$\begin{matrix} M a r k s & N o . o f S t u d e n t s 0 - 10 & 5 10 - 20 & 5 20 - 30 & 13 30 - 40 & 8 40 - 50 & 9 \end{matrix}$

$\begin{matrix} C l a s s I n t e r v a l & x_{i} & f_{i} & f_{i} x_{i} 0 - 10 & 5 & 5 & 25 10 - 20 & 15 & 5 & 75 20 - 30 & 25 & 13 & 325 30 - 40 & 35 & 8 & 280 40 - 50 & 45 & 9 & 405 \end{matrix}$

$\sum f_{i} = 40$ & $\sum f_{i} x_{i} = 1110$

Mean
$= \frac{1110}{40}$

$= 27.75$

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Similar questions

The following table gives the marks obtained by the students of a class in an exam out of 50.

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Q. Question 10
The following table shows the cumulative frequency distribution of marks of 800 students in an examination.

\begin{matrix} M a r k s & N u m b e r o f s t u d e n t s B e l o w 10 & 10 B e l o w 20 & 50 B e l o w 30 & 130 B e l o w 40 & 270 B e l o w 50 & 440 B e l o w 60 & 570 B e l o w 70 & 670 B e l o w 80 & 740 B e l o w 90 & 780 B e l o w 100 & 800 \end{matrix}

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The following table gives the marks obtained by the students of a class in an exam out of 50. MarksNo. of StudentsBelow 105Below 2010Below 3023Below 4031Below 5040 (i) Convert the cumulative frequency distribution into a regular frequency distribution. (ii) Find the mean.

The correct option is C 27.75 MarksNo. of Students0−10510−20520−301330−40840−509 Class Intervalxififixi0−10552510−201557520−30251332530−4035828040−50459405 ∑fi=40 & ∑fixi=1110 Mean =111040 =27.75