The following table gives the production yield per hectare of wheat of 100 farms of a village.

$\begin{matrix} P r o d u c t i o n y i e l d (k g / h a) & 50 - 55 & 55 - 60 & 60 - 65 & 65 - 70 & 70 - 75 & 75 - 80 N u m b e r o f f a r m s & 2 & 8 & 12 & 24 & 38 & 16 \end{matrix}$

Change the distribution to a 'more than type' distribution and draw its ogive.Using ogive,find the median of the given data.

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Solution

The frequency distribution table of more than type is as follows:

Production yield (kg/ha)(lower class limits) Cumulative frequency (cf)

More than 50 2+98=100

More than 55 8+90=98

More than 60 12+78=90

More than 65 24+54=78

More than 70 38+16=54

More than 75 16

Taking the lower class limits on x-axis and their respective cumulative frequencies on y-axis, its ogive can be obtained as follows:

Here, N=100,

⇒ $\frac{N}{2}$ =50

Mark the point A whose ordinate is 50 and its x-coordinate is 70.5.

The median of the data is 70.5

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Similar questions

Production yield (in kg\ha)	$50 - 55$	$55 - 60$	$60 - 65$	$65 - 70$	$70 - 75$	$75 - 80$
Number of farms	$2$	$8$	$12$	$24$	$38$	$16$

100

production of fields	$50 - 55$	$55 - 60$	$60 - 65$	$65 - 70$	$70 - 75$	$75 - 80$
Numbers of farms	$2$	$8$	$12$	$24$	$38$	$16$

Production yield (kg/ha)	50−55	55−60	60−65	65−70	70−75	75−80
Number of farms	2	8	12	24	38	16

Production yield in kg/hectare	50-55	55-60	60-65	65-70	70-75	75-80
Number of farms	2	8	12	24	38	16

\begin{matrix} P r o d u c t i o n y i e l d (i n k g / h a) & 50 - 55 & 55 - 60 & 60 - 65 & 65 - 70 & 70 - 75 & 75 - 80 N u m b e r o f f a r m s & 2 & 8 & 12 & 24 & 38 & 16 \end{matrix}

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Production yield (kg/ha)(lower class limits)	Cumulative frequency (cf)
More than 50	2+98=100
More than 55	8+90=98
More than 60	12+78=90
More than 65	24+54=78
More than 70	38+16=54
More than 75	16