The following table presents the number of illiterate males in the age group (10–34) in a town
Age Group10−1415−1920−2425−2930−34Number of males300980800580290
Draw a histogram to represent the above data
The correct option is A.
Age Group10−1415−1920−2425−2930−34Number of males300980800580290
The given frequency distribution is not continuous. So, we shall first convert it into a continuous frequency distribution.
The difference between the lower limit of a class and the upper limit of the preceding class is 1 i.e. h=1. To convert the given frequency distribution into a continuous frequency distribution, we subtract
h2=12=0.5 from each lower limit and add h2=0.5 to each upper limit. The distribution so obtained is as given below:
Age Group9.5−14.51.5−19.519.5−24.524.5−29.529.5−34.5Number of Females300980800580290
The histogram of the above frequency distribution is given in the figure above.