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Byju's Answer

Standard IX

Physics

Distance-Time Graph

The following...

Question

The following table represents the distance of a car at different instants in a fixed direction.
Time (s) 0 1 2 3 4 5
Distance (m) 0 10 20 30 40 50
Use the table to calculate the displacement of car at $t = 2.5 s$ and $t = 4.5 s$ .

20 m

and

4 m

respectively

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2.5 m

and

4.5 m

respectively

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25 m

and

45 m

respectively

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25 m

and

50 m

respectively

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Solution

The correct option is C $25 m$ and $45 m$ respectively
if we draw Time vs Distance graph for given value we will get a linear line.
so, it is apparent that at t $=$ 2.5 s, displacement is 25 m and at t $=$ 4.5 s, displacement is 45 m.

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Q. The following table represents the distance of a car at different instants in a fixed direction.

Time (s)	0	1	2	3	4	5
Distance (m)	0	10	20	30	40	50

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$\begin{matrix} T i m e (s) & 0 & 1 & 2 & 3 & 4 D i s p l a c e m e n t (m) & 0 & 5 & 10 & 15 & 20 \end{matrix}$

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Q. Following table gives the displacement of a car at different instants of time.

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The following table represents the distance of a car at different instants in a fixed direction.Time (s)012345Distance (m)01020304050Use the table to calculate the displacement of car at t=2.5s and t=4.5s.

The correct option is C 25m and 45m respectivelyif we draw Time vs Distance graph for given value we will get a linear line.so, it is apparent that at t = 2.5 s, displacement is 25 m and at t = 4.5 s, displacement is 45 m.

The following table represents the distance of a car at different instants in a fixed direction.
Time (s) 0 1 2 3 4 5
Distance (m) 0 10 20 30 40 50
Use the table to calculate the displacement of car at $t = 2.5 s$ and $t = 4.5 s$ .

The correct option is C $25 m$ and $45 m$ respectively
if we draw Time vs Distance graph for given value we will get a linear line.
so, it is apparent that at t $=$ 2.5 s, displacement is 25 m and at t $=$ 4.5 s, displacement is 45 m.