Question

The following table shows number of males and females of a locality in different age groups.

$\begin{array}{cccc}\text{Age~in~years}& 10-20& 21-50& \text{Above~50}\\ \text{Male}& 12& 16& 4\\ \text{Female}& 8& 14& 6\end{array}$

If one person is selected at random, find the probability that the selected person is male

• A. $\frac{8}{15}$
• B. $\frac{7}{15}$
• C. $\frac{13}{60}$
• D. $\frac{1}{4}$

Answer 1

The correct option is A

$\frac{8}{15}$

Total number of people in the given locality = 12 + 16+ 4 + 8 + 14 + 6

= 60

Number of males = 12 + 16+ 4

= 32

$\text{Probability that selected person is male}=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

$=\frac{\text{Number of males}}{\text{Total number of people in the given locality}}$

= $\frac{32}{60}$

= $\frac{8}{15}$