Question

The following table shows number of males and females of a locality in different age groups.

$\begin{array}{cccc}\text{Age in years}& 10-20& 21-50& \text{Above 50}\\ \text{Male}& 12& 16& 4\\ \text{Female}& 8& 14& 6\end{array}$

If one person is selected at random, find the probability of getting a female.

• A. $\frac{8}{15}$
• B. $\frac{7}{15}$
• C. $\frac{13}{60}$
• D. $\frac{1}{4}$

Answer 1

The correct option is B

$\frac{7}{15}$

Total number of people in the given locality = 12 + 16+ 4 + 8 + 14 + 6

= 60

Number of females = 8 + 14+ 6

= 28

$\text{Probability of the person selected is female}=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

$=\frac{\text{Number of females}}{\text{Total number of people in the given locality}}$

= $\frac{28}{60}$

= $\frac{7}{15}$