The following table shows the frequency distribution of the ages of 35 people. Find the mean of the data. ClassInterval0−1010−2020−3030−4040−50Frequency(f)5151023
A
16.5
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B
32.7
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C
20.1
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D
45.8
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Solution
The correct option is C 20.1 Here, class mark of the first interval =Lowerclasslimit+Upperclasslimit2 =0+102=5
Similarly, we can find the midpoints of all the class intervals. Class Interval0−1010−2020−3030−4040−50Frequency(fi)5151023class mark(xi)515253545fixi2522525070135