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Question

The following table shows the frequency distribution of the ages of 35 people. Find the mean of the data.
Class Interval0−1010−2020−3030−4040−50Frequency (f)5151023

A
16.5
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B
32.7
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C
20.1
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D
45.8
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Solution

The correct option is C 20.1
Here, class mark of the first interval =Lower class limit + Upper class limit2
=0+102=5

Similarly, we can find the midpoints of all the class intervals.
Class Interval0101020203030404050Frequency (fi)5151023class mark (xi)515253545fixi2522525070135

fi = 5 + 15 + 10 + 2 + 3
= 35

fixi = 25 + 225 + 250 + 70 + 135
= 705

Mean=fixifi
=70535
=20.1

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