1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The following table shows the frequency distribution of the diameters of 40 bottles. Find the mean of the data. Diameter (mm)35âˆ’3940âˆ’4445âˆ’4950âˆ’5455âˆ’60Frequency61215107

A
45
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
37
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
47
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
55
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 47Diameter(mm)35−3940−4445−4950−5455−60Frequency(f)61215107Mid-Point(x)3742475257fx222504705520399 Here, the mid-point of each interval =Lower class limit + Upper class limit2 =35+392=37 Similarly, we can find mid-points of all the class interval. Now Mean=∑fixi∑fi Mean=222+504+705+520+39950=235050 ∴Mean=47

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Mean
MATHEMATICS
Watch in App
Join BYJU'S Learning Program