The following table shows the no- of marks obtained by 41 students of a class- -3 MARKS-WhineMarks - 20 - 15 - 17 - 30 - 22 - 25 -obtained - - - - - - WhlineFrequency - 10 - 2 - 5 - 4 - 12 - 8 Whline end array Find the median of marks obtained

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Median from Frequency Distribution Table

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Question

The following table shows the no. of marks obtained by 41 students of a class: [3 MARKS]
$\begin{matrix} M a r k s & 20 & 15 & 17 & 30 & 22 & 25 o b t a i n e d F r e q u e n c y & 10 & 2 & 5 & 4 & 12 & 8 \end{matrix}$
Find the median of marks obtained

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Solution

Formula: 1 Mark
Solution: 2 Marks

We arrange the data in ascending order and prepare the cumulative frequency table as given below:

$\begin{matrix} M a r k s o b t a i n e d & F r e q u e n c y & C u m u l a t i v e f r e q u e n c y 15 & 2 & 2 17 & 5 & 7 20 & 10 & 17 22 & 12 & 29 25 & 8 & 37 30 & 4 & 41 \end{matrix}$

Here, n = 41, which is odd
$∴$ Median = marks obtained by ${(\frac{41 + 1}{2})}^{t h}$ student. = marks obtained by $21^{s t}$ student.
But, 21 comes corresponding to the cumulative frequency 29 and the term corresponding to the cumulative frequency 29 is 22.
Hence, the median of marks is 22.

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The following table shows the no. of marks obtained by 41 students of a class: [3 MARKS] Marks201517302225obtainedFrequency10254128 Find the median of marks obtained

The following table shows the no. of marks obtained by 41 students of a class: [3 MARKS]
$\begin{matrix} M a r k s & 20 & 15 & 17 & 30 & 22 & 25 o b t a i n e d F r e q u e n c y & 10 & 2 & 5 & 4 & 12 & 8 \end{matrix}$
Find the median of marks obtained