Question

The following table shows the number of boxes and packs of candies won by the participants of two teams in a competition. If each box contains 12 candies and each pack contains 7 candies, which team won the most number of candies?

$\begin{array}{ccc}& \text{Team A}& \text{Team B}\\ \text{Participant 1}& \text{7 packs}& \text{4 packs}\\ \text{Participant 2}& \text{3 boxes}& \text{6 boxes}\end{array}$

• A. Team B
• B. Both teams won an equal number of candies.
• C. Team A

Answer 1

The correct option is A Team B

Number of candies in 1 box = 12
Number of candies in 1 pack = 7

$$\begin{array}{ccc}& \text{Number of candies won by}& \text{Number of candies won by}\\ & \text{Team A}& \text{Team B}\\ \text{Participant 1}& \text{7 pack = 7}\times 7=49\text{candies}& \text{4 pack = 7}\times 4=28\text{candies}\\ \text{Participant 2}& \text{3 boxes = 12}\times 3=36\text{candies}& \text{6 boxes}=12\times 6=72\text{candies}\end{array}$$
The calculation of 12$\times$3 is as follows:


The calculation of 12$\times$6 is as follows:


Number of candies won by Team A = 49 + 36 = 85
Number of candies won by Team B = 28 + 72 = 100
100 > 85, so Team B won more candies.