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Question

The following table shows the test a student performed on four different aqueous solution which are X, Y, Z and W. Based on the observations provided, identify the action present.
Chemical testObservationConclusion
To solution X, ammonium hydroxide is added in minimum quantity first and then in excess.A dirty white precipitate is formed which dissolves in excess to form a clear solution.
To solution Y ammonium hydroxide is added in minimum quantity first and then in excess.A pale blue precipitate is formed which dissolves in excess to form a clear inky blue solution.
To solution W a small quantity of sodium hydroxide solution hydroxide solution is added and then in excess.A white precipitate is formed which remains insoluble.
To a salt Z calcium hydroxide solution is added and then heated. A pungent smelling gas turning moist red litmus paper blue is obtained.

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Solution

(i) The conclusion is Zn2+ ion is present. When NH4OH solution is added to ZnSO4 we get white precipitate of Zn(OH)2.
ZnSO4+2NH4OH(NH4)2SO4+Zn(OH)2
These white ppt dissolve in excess of NH4OH solution.
Zn(OH)2+2(NH4)2SO4+2NH4OH[Zn(NH3)4]SO4+4H2O

(ii)The conclusion is Cu2+ ion is present. The solution Y is copper sulphate solution. With NH4OH solution it gives pale blue precipitate of Cu(OH)2.
CuSO4+2NH4OH(NH4)2SO4+Cu(OH)2
With excess NH4OH solution this solution turns deep blue in colour.
(NH4)2SO4+Cu(OH)2+2NH4OH[Cu(NH3)4]SO4+4H2O

(iii) The conclusion is Ca2+ ion is present. The solution W is calcium chloride solution. With NaOH solution it gives white precipitates of Ca(OH)2 which are insoluble in excess.
CaCl2+2NaOH2NaCl+Ca(OH)2

(iv) The conclusion is NH4+ ion is present. The salt Z is ammonium chloride. With NaOH solution it libreates NH3 gas which is alkaline in nature.
NH4Cl+NaOHΔNaCl+H2O+NH3

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