Question

The following table shows the yearwise strength of a school

Year	2010−11	2011−12	2012−13	2013−14	2014−15
No. of students	950	1125	1400	1750	1900

Represent the above data by a bar graph.

Answer 1

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the time intervals in years at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 50 students
Step 4: Then the height of the various bars are:
$$\begin{gathered} \mathrm{Number}\mathrm{of}\mathrm{students}\mathrm{in}\mathrm{the}\mathrm{year}2010-11=\left(\frac{1}{50}\times 950\right)=19\mathrm{small}\mathrm{divisions} \\ \mathrm{Number}\mathrm{of}\mathrm{students}\mathrm{in}\mathrm{the}\mathrm{year}2011-12=\left(\frac{1}{50}\times 1125\right)=22.5\mathrm{small}\mathrm{divisions} \\ \mathrm{Number}\mathrm{of}\mathrm{students}\mathrm{in}\mathrm{the}\mathrm{year}2012-13=\left(\frac{1}{50}\times 1400\right)=28\mathrm{small}\mathrm{divisions} \\ \mathrm{Number}\mathrm{of}\mathrm{students}\mathrm{in}\mathrm{the}\mathrm{year}2013-14=\left(\frac{1}{50}\times 1750\right)=35\mathrm{small}\mathrm{divisions} \\ \mathrm{Number}\mathrm{of}\mathrm{students}\mathrm{in}\mathrm{the}\mathrm{year}2014-15=\left(\frac{1}{50}\times 1900\right)=38\mathrm{small}\mathrm{divisions} \end{gathered}$$

Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below: