The following titration method is given to determine the total content of the species with variable oxidation states. Answer the question given at the end of it.
A quantity of 25.0 mL of solution containing both Fe2+ and Fe3+ ions is titrated with 25.0 mL of 0.02 M KMnO4 (in dilute H2SO4). As a result, all of the Fe2+ ions are oxidised to Fe3+ ions. Next 25 mL of the original solution is treated with Zn metal. Finally, the solution requires 40.0 mL of the same KMnO4 solution for oxidation to Fe3+.
MnO4−+5Fe2++8H+→Mn2++5Fe3++4H2O
The molar concentration of Fe2+ in the original solution is :