You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reactivity with Air and Water (Group 2)

The following...

Question

The following two reactions of $H {N O}_{3}$ with $Z n$ are given as (equations are not balanced)

$Z n + c o n c . H {N O}_{3} ⟶ Z n {({N O}_{3})}_{2} + X + H_{2} O . . . . . . . . . . . . . . . . . . (A)$

$Z n + d i l . H {N O}_{3} ⟶ Z n {({N O}_{3})}_{2} + Y + H_{2} O . . . . . . . . . . . . . . . . . . . . (B)$

In reactions $A$ and $B$ , the compounds $X$ and $Y$ respectively are

{N O}_{2}

and

N O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{N O}_{2}

and

N_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N O

and

{N O}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{N O}_{2}

and

{N H}_{4} {N O}_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D ${N O}_{2}$ and ${N H}_{4} {N O}_{3}$
$Z n$ added in concentrated $H {N O}_{3}$

$Z n + 4 H {N O}_{3} ⟶ Z n {({N O}_{3})}_{2} + 2 {N O}_{2} + 2 H_{2} O$

$Z n$ added in dilute $H {N O}_{3}$

$4 Z n + 10 H {N O}_{3} ⟶ 4 Z n {({N O}_{3})}_{2} + N_{2} O + 5 H_{2} O$

Option B is correct.

Suggest Corrections

Similar questions

Z n + c o n c . H N O_{3} (h o t) \to Z n (N O_{3})_{2} + X + H_{2} O

Z n + d i l . H N O_{3} (cold) \to Z n (N O_{3})_{2} + Y + H_{2} O

H N O_{3}

\to Z n (N O_{3})_{2} + X + H_{2} O

H N O_{3}

\to Z n (N O_{3})_{2} + Y + H_{2} O

H N O_{3}, C o n c . H N O_{3}

H N O_{3}

H N O_{3}

a, b, c

X, Y, Z

(a + b + c)

Z n + H N O_{3} \to Z n (N O_{3})_{2} + " X " + H_{2} O

20 %

Z n + H N O_{3} \to Z n (N O_{3})_{2} + " Y " + H_{2} O

70 %

Z n + H N O_{3} \to Z n (N O_{3})_{2} + " Z " + H_{2} O

6 %

Oxidant and Reductanct in the following reactions are respectively

$10 H^{+} (a q) + 4 Z n (s) + N O_{3}^{-} (a q) \to 4 Z n^{2 +} (a q) + N H_{4}^{+} (a q) + 3 H_{2} O (l)$

I : Z n + d i l . H_{2} S O_{4} ⟶ Z n S O_{4} + H_{2}

I I : Z n + c o n c . H_{2} S O_{4} ⟶ Z n S O_{4} + S O_{2} + H_{2} O

I I I : Z n + H N O_{3} ⟶ Z n {({N O}_{3})}_{2} + {N H}_{4} {N O}_{3} + H_{2} O

Join BYJU'S Learning Program