Question

The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground.

(a) Find the length of the ladder.

Answer 1

Step: Finding the length of the ladder

Given, height of the wall AB = 8m and

Distance of ladder's foot from the wall BC = 6m.

Using the Pythagoras theorem, we get:


$\Rightarrow (AC{)}^2=(AB{)}^2+(BC{)}^2$

$\Rightarrow (AC{)}^2=(8{)}^2+(6{)}^2$

$\Rightarrow (AC{)}^2=64+36$

$\Rightarrow (AC{)}^2=100$

$\Rightarrow \left(AC\right)=\sqrt{100}$

$\therefore AC=10m$

Hence, the length of the ladder = 10 m.